calculate charge on 2 microfarad capacitor
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Answer:
n steady state the capacitor becomes open,
So current through the circuit, i=
27×10
3
9
And Voltage across the capacitor, V
c
=i×15 kΩ=15×10
3
×
27×10
3
9
=
3
15
=5V
Charge through the capacitor, q=CV
c
=9×10
−6
×5
q=45×10
−6
C
q=45μC.
Explanation:
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