Question

calculate circumference, diameter and area of 4th Bohr orbit for Be^3+ ion.​

Answer 1

Answer:

Sorry i dont know

Explanation:

Answer 2

Answer:

C= 13.29 D= 4.232 A= 14.06

Explanation:

radius = 0.529 x $n^{2}$/z
= 0.529 x 16/4

= 2.116 Å

diameter= 2 x r
              = 2 x 2.116

= 4.232 Å

area= π$r^{2}$

= 3.14 x $2.116^{2}$

= 14.06 $Å^{2}$