Question

calculate compound interest on rup 1000 over a period of 1 year at 10% per annum if interest is compounded half yearly​

Answer 1

Answer:

A= 1102.5

C. I. =102.5

Step-by-step explanation:

given,

P = 1000

t = 1 year half yearly 2

r= 10% half yearly 5%

find it a and ci

so,

A = p( 1+r/100)^t

A= 1000( 1+ 5/100)^ 2

A = 1000(21/20)^2

A= 1000(1.1025)

A= 1102.5

C. I. = A-P

C. I. =1102.5-1000

C. I. =102.5

Answer 2

$\huge\mathbb{Solution}}$

As interest is compounded half yearly so there will be 2 conversion periods in a year

So n= 2

Rate of interest for 6 months rate=

$\large\bold{= 1/2*10% =5%}}$

$\large\bold{ A = p (1 + r/100)^ n}}$

$\large\bold{ A = 1000 ( 1 + 5/100)^2}}$

$\large\bold{ = 1000 (105/100)^2}}$

[/tex]\large\bold{= ₹1102.50}}[/tex]

Compound interest=$\Large\bold{A-p = 1102.50-1000= ₹102.50}}$