calculate conc of each ion present in 10^-3M, 200ml H2SO4
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We proceed as follows
We calculate that how many free hydrogens are present in H2SO4… Now we know it will ionise as 2H+ and 1SO4- . thus one molecule can release 2H+ in an aqueous soln
Now we calculate the concentration of H+ ions so if there's 10–3 M of H2SO4 after dissolving it will be 2×10–3M of it
Finally we calculate the pH as we know it the negative of log of the H+ concentration for this case it would be -log(2×10–3)= 3-log2 ≈ 2.69
Thus pH of the given soln ≈2.69
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