Question

calculate concentration of nitric acid in moles per litre in a sample having density 1.41gmL^-1 ,mass percent of nitric acid being 69%​



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Answer 1

Answer:

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Answer:

Solution :

Mass percent of nitric acid in the sample = 69 % [Given]

Thus, 100 gof nitric acid contains 69 g of nitric acid by mass.

Molar mass of nitric acid (HNO_3)

= (1 + 14 + 3(16)) g mol^-1

= 1 + 14 + 48

= 63 g mol^-1

Number of moles in 69 g of HNO,

= 69g/63g mol^-1

= 1.095 mol

Volume of 100g of nitric acid solution

= Mass of solution/density of solution

= 100g/1.41gmL

= 70.92 mL

= 70.92 x10^-3 L

Concentration of nitric acid

= 1.095 mole/70.92x10^-3L

= 15.44 mol/L

=> Concentration of nitric acid = 15.44 mol/L