calculate cos A and tan A.
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Step-by-step explanation:
Given, sinA=43
⇒DCBC=43
⇒BC=3k and AC=4k
where k is the constant of proportionality.
By Pythagoras theorem, we have
AB2=AC2−BC2=(4k)2−(3k)2=7k2
⇒AB=7k
So, cosA=ACAB=4k7k=47
And tanA=ABBC=7k3k=
please follow me.
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