Question

Calculate coulomb force between alpha particle and proton separated by 5.12×10^-15

Answer 1

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Answer 2

Given :

Separation between alpha particle and proton is , $r=5.12\times 10^{-15}\ m$ .

To find :

Force between them .

Solution :

Charge on proton , $q_p=1.6\times 10^{-19}\ C$ .

Now , we know charge on  alpha particle is twice the charge on proton .

Therefore , $q_\alpha=2\times 1.6\times 10^{-19}\ C$ .

We know , force is given by :

$F=\dfrac{kq_p\ q_\alpha}{r^2}$

Here , $k=9\times 10^9\ N\ m^2\ C^{-2}$

Putting all values in above equation .

We get :

$F=\dfrac{9 \times 10^9\times 1.6\times 10^{-19} \times 2\times 1.6\times 10^{-19}}{(5.12\times 10^{-15})^2}\\\\F=17.58\ N$

Therefore , coulomb force between alpha particle and proton is 17.58 N .

Learn More :

Electrostatics

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