Question

calculate current density in a copper wire ( cross section area 1.0 × 10^-7 m^2 ) carrying current off 1.5 ampere​

Answer 1

Question :-

→ Calculate current density is a copper wire ( cross section area 1.0 × 10^-7 m²) carrying current of 1.5 ampere .

Answer :-

$\to \boxed{ \sf current \: density \: (j) = 1.5 \times {10}^{7} \: } \sf \frac{ampere}{ {meter}^{2} }$

To find :-

→ current density (j)

Formula used :-

$\star \: \sf current \: density(j) = \frac{current \: (i)}{cross \: sectional \: area \: }$

Explanation :-

According to the question,

→ Current density (j) = ?

→ area of cross section (A) = 1.0× 10^-7 m²

→ current ( i ) = 1.5 ampere

apply the given formula

$\to \: \sf current \: density \: (j)) = \frac{1.5}{1.0 \times {10}^{ - 7} } \\ \\ \to \boxed{ \sf current \: density \: (j) = 1.5 \times {10}^{7} \: } \sf \frac{ampere}{ {meter}^{2} }$

_________________

Current density (j) :-

→ current flow in a material per unit cross sectional area of that material is known as current density .

It is denoted by "j" .

_________________