calculate current in the circular coil of radius 5cm and 100 turns to produce a field of 2x12T at its centre
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Explanation:
B=
2r
nμ
0
i
n=100,r=5cm=0.05m
B
=6×10
−5
T
i=
nμ
0
2rB
=
100×4π×10
−7
2×0.05×6×10
−5
=
6.28
3
×10
−1
=0.0477≈48mA
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