Calculate de Broglie wavelength of alpha particle accelerated through a potential difference of 10^7
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Answer: 0.000031
Explanation:
λ=h / √2mE
= h / √2mαQαV
On putting Qα=2×1.6×10^−19
mα = 4mp = 4×1.67×10^−27kg
⇒λ=0.101 / √V in Å
0.101 / 3162.27
=0.000031
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