Question

Calculate de broglie wavelength of an electron travelling at 1 of the speed of light

Answer 1

https://www.askiitians.com/forums/Inorganic-Chemistry/20/25656/plz-helpplzzz.htm

λ = h/mc

In your problem, velocity = c/100 ( since the velocity is 1 %)

Sub c=c/100 in above equation, You will get λ = 100 h/mc

Sub values of h,m and c. Arrange the powers of 10. The answer will be 2.42 x 10-10.

(lamda) = h/mv (h is planks constant , h = 6.6*10-34 & m is mass of particle)

v = 1% of speed of light = C/100 (C is speed of light & C=3*108)

lamda = h/mv

=100h/mC (m = 9.1*10-31kg , mass of electron)

= 0.241*10-9 m

=0.241nm or 2.41(angstorm)

Answer 2

(lamda) = h/mv

(h is planks constant , h = 6.6x10^-34 & m is mass of particle)

v = 1% of speed of light = C/100

(C is speed of light & C=3x10^8)

lamda = h/mv
=100h/mC

(m = 9.1x10-31kg , mass of electron)

lamda=100x6.6x10^-34 / 9.1x10-31xC=3x10^8

lamda=6.6x10^-32 / 27.3x10^-23

lamda= 0.241x10-9 m

lamda=0.241nm or 2.41(angstorm)