Calculate de Broglie wavelength of neutron of energy 12.8MeV.
Answers
Answer ⇒ The wavelength of the neutron is 7.99 fm.
Explanation ⇒ Kinetic energy = 12.8 MeV.
∴ K.E. = 12.8 × 10⁶ eV.
∴ 1/2 × mv² = 12.8 × 10⁶ × 1.6 × 10⁻¹⁹
1.6749 × 10⁻²⁷ × v² = 25.6 × 1.6 × 10⁻¹³
∴ v² = 24.45 × 10¹⁴
∴ v = 4.94 × 10⁷ m/s.
Using the formula of the de-broglie wavelength,
λ = h/mv
∴ λ = (6.626 × 10⁻³⁴)/(1.6749 × 10⁻²⁷ × 4.94 × 10⁷)
∴ λ = 0.799976 × 10⁻¹⁴
∴ λ = 7.99 × 10⁻¹⁵ m.
∴ λ = 7.99 fm.
Hence, the wavelength of the neutron is 7.99 fm.
Hope it helps.
Answer:
Explanation:
∴ K.E. = 12.8 × 10⁶ eV.
∴ 1/2 × mv² = 12.8 × 10⁶ × 1.6 × 10⁻¹⁹
1.6749 × 10⁻²⁷ × v² = 25.6 × 1.6 × 10⁻¹³
∴ v² = 24.45 × 10¹⁴
∴ v = 4.94 × 10⁷ m/s.
Using the formula of the de-broglie wavelength,
λ = h/mv
∴ λ = (6.626 × 10⁻³⁴)/(1.6749 × 10⁻²⁷ × 4.94 × 10⁷)
∴ λ = 0.799976 × 10⁻¹⁴
∴ λ = 7.99 × 10⁻¹⁵ m.
∴ λ = 7.99 fm.