Question

Calculate de broglie wavelength of the electron in first bohr's orbit

Answer 1

De Broglie's wavelength,

λ = the circumference (2πr) of orbit for n=1. That is, an electron in the first bohr orbit. To find the circumference,

E = (-) ke² / 2r. For the ground state (n=1) E = -13.60 eV.

λ = 3.326^-10 m. The De Broglie wavelength for an electron in the first bohr orbit of a hydrogen atom is 3.326^-10 m.