calculate Delta G° (standard Gibb's energy ) for the reaction Ni(s)+2Ag(aw) > Ni 2+ (aq) + 2Ag (s) (given E°Ni2+/Ni = - 0.25 v ,E° Ag+/Ag = 0.80 v
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Answer:
E=E
∘
−
n
0.0592
log
[R]
[P]
ateq
m
E=0
logK=
0.0592
nE
∘
Ni→Ni
2+
+2e
−
Ag
+
+e
−
→Ag
E
cell
∘
=0.80+0.26
=1.06V
logK=
0.0592
2×1.06
K=6.46×10
35
W
max
=nFE
∘
W
max
=2×96500×1.06
=204580J
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