calculate distance moved by a particle in 10 seconds if initially it has velocity 2 metre per second and a retardation of 1 metre per second square
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Given :-
initial velocity (u)= 2m/s
acceleration (a) = -2 m/s2
time (t) = 10 s
s=?
From second equation of motion,
s=ut + 1/2 at2
substituting the values,
= 2×10 + 1/2 × -2 ×10×10 m
solve this you got your answer
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