Calculate E° cell, ∆ G ° and equlinrium constant for the reaction2 Cu+_________Cu2+ +Cu E° Cu+ | Cu= 0.52v and E° Cu2+| cu+= 0.16 v
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Answer:
1.2×10raisedto 6
Explanation:
The disproportionation reaction is
2Cu
+
(aq)⟶Cu(s)+Cu
2+
(aq)
E
cell
=E
cell
o
−
n
0.0591
log
[Cu
+
]
2
[Cu
2+
]
E
cell
=E
cell
o
−
1
0.0591
logQ
Now,
E
cell
o
=E
Cu
+
/Cu
o
−E
Cu
2+
/Cu
+
o
E
cell
o
=0.52−0.16=0.36 V
At equilibrium
E
cell
=0 V;
E
cell
=E
cell
o
−
1
0.0591
logQ
0=E
cell
o
−
1
0.0591
logK
c
E
cell
o
=0.0591logK
c
0.36=0.0591logK
c
logK
c
=
0.0591
0.36
=6.09
∴K
c
=1.2×10
6
The equilibrium constant for the disproportionation reaction is 1.2×10
6
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