Question

Calculate Ecell for the cell Al/Al3+(0.01M)||Fe2+(0.02M)/Fe Given that E°Al3+/Al=-1.66,E°Fe2+/Fe=-0.44

Answer 1

Al → Al+3  +  3e-
MULTIPLYING BY 2
Fe+2  +  2e-  →Fe
MULTIPLYING BY 3
⇒ADDING ABOVE EQUATIONS GIVES
2Al + 3Fe+2 →2Al+3 + 3Fe

ECELL= E°CELL - 0.059/6 LOG (CONC.Al+3/CONC. OF Fe+2)
WHICH GIVES
= 1.66-0.44+0.00296= 1.22V
HOPE U UNDERSTAND AND ANSWER IS RIGHT

Answer 2

Answer:

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