Calculate effective atomic number of AgCl2 And PdCl4
Answers
Answer:49 and 50
Explanation: Effective atomic number or EAN to be precise is a certain number that denotes or shows the penultimate picture of electrons linked or surrounding the nucleus of a particular metal in it's complex compound . It is basically formed by the atom of the metal electrons and the electrons which are participating in bonding among the surrounding electron donating atoms.
For the first example we have Agcl2.
Formula of EAN: (atomic no of metal)- (no of electrons lost during the making of the compund or specifically the oxidation state of this) + 2* no of lignads*no of co ordinate bond formed by the ligand
OR
EAN= Z-x+2nL
Z= 47
x= XAg + Xcl2 =0 (net charge on this compund is zero)
or,
XAg + 2(-1) =0
Therefore X is +2
n= 1 only one ligand is present
Here, L=2 Di dentate ligand
EAN= 47-2+2*1*2
EAN= 49
Similarly for Pdcl4
Z=46
L= 4
n= 1
x= XPd + Xcl = 0
XPd + 4(-1)= 0
Oxidation state of Pd, x= 4
EAN= 46 - 4 + 2*1*4
= 50