calculate effective resistance in the following circuit
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effective resistance should be
R1+R2/R1R2
=12+3/12×3
=15/36 ohm
whereas
V=I×R
I=V/R
therefore I= 6÷15/36
=6×36/15
=216/15
=14.4 A
R1+R2/R1R2
=12+3/12×3
=15/36 ohm
whereas
V=I×R
I=V/R
therefore I= 6÷15/36
=6×36/15
=216/15
=14.4 A
rashmitha71:
R u right
yes
and thus current will be 15 /6 =2.5 Ampere and effective resistance will be 2.4ohm
2.4 .4=6.4
add Resistance in Series Also Kumarsomu
so v=ir and i = 6/6.4=0.9375 amper
sorry Kushal
i think it would be enough to solve the question
tnk u
np
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Hope it helps you
thank you
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