Question

Calculate electrical conductivity in copper if the mean free path of electron is 4×10-8m , electron density is 8.4×1028 and average thermal velocity of electron is 1.6×106 ms-1. (τ = ʎ/v) (Given, ʎ= 4×10-8m, v=1.6×106 ms-1).​

Answer 1

Answer:

Energy2eV

eV

0

=2eV

⇒V

0

=2

Now, electric field E=

4×10

−8

2

=0.5×10

8

=5×10

7

V/m