Question

calculate emperical formula and molecular formula if molecular weight is 244 and carbon is 69.41% and Hydrogen is 4.29%​

Answer 1

Answer:

      C₂₀H₁₅

Explanation:

Element      %by mass    Atomic Mass   Relative no of atoms   Whole no ratio

  C               69.41 %               12                 69.41 / 12 =  5.8          5.8/4.3 = 1.35

  H                4.29 %                 1                   4.29 / 1 = 4.3              4.3/4.3 = 1

  C : H = 1.35 : 1     (multiply by 3)

  C : H = 4 : 3

Empirical formula = C₄H₃

Empirical mass = 12×4 + 3×1 = 48 + 3 = 51

Molecular formula = (C₄H₃)ₙ

n = molecular mass / empirical mass = 244 / 51 = 4.8 ≈ 5

(C₄H₃)ₙ = (C₄H₃)₅ = C₂₀H₁₅

IDK if this is the right answer please check if u have answer key or something

But this is the right method to do