calculate energy and power consumed by 8 ohm resistor in one hour when 4 ohm and 6 ohm 8 ohm are connected - (1) in series (2) in parallel, across battery of 24 volt
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Answer:
14.22 W
72 W
Explanation:
calculate energy and power consumed by 8 ohm resistor in one hour when 4 ohm and 6 ohm 8 ohm are connected - (1) in series (2) in parallel, across battery of 24 volt
When Connected in series
Total Resistance = 4 + 6 + 8 = 18 Ω
Voltage = 24 V
Current = 24/18 = 4/3 A
power consumed by 8 ohm resistor = I²R
= (4/3)² * 8
= 128/9
= 14.22 W
When Connected in Parallel
Total Resistance = 1/(1/4 + 1/6 + 1/8) = 24/(6 + 4 + 3) = 24/13 Ω
Total Current = 24/(24/13) = 13 A
Current through 8 Ω resistor = 24/8 = 3 A
power consumed by 8 ohm resistor = 3² * 8 = 72 W
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