Question

calculate energy of one mole of nitrogen gas 27 Celsius compare the energy of one mole of hydrogen gas at this temperature with the corresponding value of Nitrogen gas

Answer 1

Answer:

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Answer 2

Answer:

Explanation:

Given

no of moles of Nitrogen $n_1=1$

Temperature of nitrogen $T_1=27^{\circ}C\approx 300\ K$

Energy associated can be expressed by

$E=\frac{3}{2}nRT$

where $R=gas\ constant$

$n=no\ of\ moles$

$T=temperature$

$E_1=1.5\times 1\times 8.314\times 300$

$E_1=3741.3\ J$

Energy of Nitrogen gas

$E_2=\frac{3}{2}nRT$

$E_2=1.5\times 1\times 8.314\times 300$

$E_2=3741.3\ J$

therefore Energy of both the gases is equal