Question

Calculate energy of one mole of photon of radiation whole wavelength 600nm

Answer 1

1 mole of photons contains 6.022×10^23 photons

Energy of one photons = E = ?

wavelength = λ = 600nm = 600×10^-9m

velocity = v = c = 3×10^8 m/s

Planck's constant = h = 6.626×10^-34Js
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E = hc/λ

E = 6.626×10^-34×3×10^8/600×10^-9

E = 6.626×3×10^-26/6×10^-7

E = 3.313×10^-36+7

E = 3.313×10^-29J
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Energy of one mole photons = Em = ?

Em = energy of one photons × 6.022×10^23

Em = E × 6.022×10^23

Em = 3.313×10^-29J × 6.022×10^23

Em = 19.95 × 10^-29+23

Em = 19.95 × 10^-6J
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Answer 2

Concept :

Energy is a physical system's ability to carry out tasks. There are many different types of energy, including heat, kinetic or mechanical energy, light, potential energy, electrical energy, and others. The capacity to perform work is energy. Energy sources can be divided into two categories: renewable and non-renewable. Energy is a phrase used to define a characteristic of the material and non-matter fields; energy is not formed of anything. For instance, it's argued that kinetic energy exists when a substance moves. There are other types of potential energy as well. Energy is necessary for life and for all living things. All the energy on Earth comes from the sun, either directly or indirectly. We must carefully select our energy sources because they have an impact on Earth's natural processes in ways that we may not be conscious of.

Given:

wavelength $600nm$.

Find, the energy of one mole of a photon of radiation's whole wavelength $600nm$.

Solution:

According to the problem,

wavelength $600nm$

$1$ mole of photons contains $6.022$ ×$10^2^3$ photons

wavelength = λ = $600nm = 600$×$10^-^9m$

velocity = v = c =$3$×$10^8 m/s$

Planck's constant = $h = 6.626$×$10^-^3^4Js$

By applying the law,

E = hc/λ

$E = 6.626$×$10^-^3^4$×$3$×$10^8/600$×$10^-9$

$E = 3.313$×$10^-29J$

Energy of one mole photons = $Em$

$Em =$ energy of one photons × $6.022$×$10^2^3$

$Em = E$ × $6.022$×$10^2^3$

$Em =$ $3.313$×$10^-29J$ × $6.022$×$10^2^3$

$Em = 19.95$ × $10^-29+23$

$Em =$ $19.95$ × $10^-6 J$

Hence the energy of one mole of photon of radiation whole wavelength $600nm$ is $19.95$ × $10^-^6J$.

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