Question

Calculate energy of one mole of photons
of radiation whose frequency is 5 x1014
Hz.​

Answer 1

Answer:

The energy of one photon (E) =hv

Here, h=6.626×10

34

js

v=5×10

14

s

−1

E=6.626×10

−34

×5×10

14

3.313×10

−19

j

Thus the energy of one mole of photons is E×A

Where A is the Avogadro number

=3.313×10

−19

j×6.022×10

−23

mol

=199.50×10

−3

jmol

Answer 2

$\checkmark$ Given:

One mole of photons  of radiation of frequency is 5 x 10¹⁴  Hz

$\checkmark$ To Find:

Calculate energy of one mole of photons

$\checkmark$ Solution:

We know that,

$\red{\bigstar \ \boxed{\rm E=hv}}$

Here,

• E = energy of photon
• h = planck's constant
• v = frequency

According to the question,

We are asked to find the energy of one mole of photons

Given that,

One mole of photons  of radiation of frequency is 5 x 10¹⁴  Hz

Hence,

• v = 5 x 10¹⁴ Hz = 5 x 10¹⁴  s⁻¹

We know that,

• h = 6.626 x 10⁻³⁴ J s

Substituting the values,

We get,

$\blue{\rm E=6.626 \times 10^{-34} \ J \ s \times 5 \times 10^{14} \ s^{-1}}$

On further simplification,

We get,

$\green{\rm \star \ E=3.313 \times 10^{-19} \ J}$

According to the question,

We are asked to find the energy of one mole of photons

Therefore,

$\orange{\rm E=3.313 \times 10^{-19} \ J \times 6.022 \times 10^{23} \ mol^{-1}}$

On further simplification,

We get,

$\pink{\rm \star \ E=199.51 \ kJ \ mol^{-1}}$

Hence,

$\checkmark$ Energy = 199.51 kJ mol⁻¹