Question

Calculate energy of one mole of photons of radiation whose frequency is 5×(10)14H2

Answer 1

Energy of one photon is given by the expression E = hV

where, h = PlancKs constant = 6.636 x 10-34 J s-1

V= Frequency of radiation = 5x 1014 Hz= 5 x 1014 s-1.

E= (6.636 x 1034 J s-1 x 5 x 1014 s-1)= 33.18 x 1020J

One mole of photon = 6.023 x 1023 photons

Therefore, Energy of one mole of photon = (6.023 x 1023 x 33.18 x 10-20 J) = 199.84 x 103 J

Energy of one mole of photon = 199.84 kJ

Answer 2

Explanation:

Energy of 1 mol quantum= Nhv

= 6.023 × 1023 × 6.626 × 10–34 × 5 × 1010

= 19.95 J mol