Question

Calculate energy of photon of radiation having wavelength 300nm

Answer 1

Explanation:

Check the attachment :)

Answer 2

Answer:

The energy of photon of radiation with wavelength 300nm is 6.626× 10⁻¹⁹ Joules.

Explanation:

Given that wavelength $\lambda = 300nm=300*10^{-9}m$

We know that    $E=\frac{h.c}{\lambda}$

where           $h=6.626*10^{-34} Js \\ c=3*10^{8}ms^{-1}$

Therefore   $E =(6.626*10^{-34})(\frac{3*10^{8}}{300*10^{-9}})Joule$

                   $E=6.626*10^{-19} Joules$

Therefore the energy of given photon equals to 6.626× 10⁻¹⁹J.