Question

Calculate enthalpy change if delta h is 22.9 fpt nh3

Answer 1

Here is your answer ↙️↙️☺️☺️❤️❤️

The balanced chemical equation for formation of NH3 would be as follows:

12N2(g) + 32H2(g)-->NH3(g) 

The energy required to break required bonds for the formation of product is calculated as:

1/2 mole of N2 will require 712 kJ·mol-1/2  = 356 kJ/mol 

3/2 mole of H2 will require 3×  436 kJ·mol-1/2 = 654 kJ/mol 

Total energy require to break the bonds = (356 + 654) kJ/mol = 1010 kJ/mol

total energy of reaction = (total energy of bonds broken) - (total energy of bonds formed)  

 -46.3 kJ/mol =1010) kJ/mol - 3(N-H)

3(N-H) = 1010 kJ/mol + 46.3kJ/mol  = 1056.3 kJ/mol 

(N-H) =  1056.3 kJ/mol /3 = 352.1kJ/mol 

Hope this helps you ☺️☺️⭐✨✨⭐✌️✌️