Question

Calculate entropy of Br2 in reaction H2 + Br2 2Hbr if ∆S = 20.1 and entropy of H2 is 130.6 and Hbr is 198.5b

Answer 1

Answer:

Using standard absolute entropies at 298K, calculate the entropy change for the system when 2.16 moles of HBr(g) react at standard conditions.

Delta S°system = J/K

Answer 2

The entropy of $Br_2$ is 246.3

Explanation:

The balanced chemical reaction is,

$Br_2(g)+H_2(g)\rightarrow 2HBr(g)$

The expression for entropy change is,

$\Delta S=\sum [n\times S_(product)]-\sum [n\times S_(reactant)]$

$\Delta S=[(n_{HBr}\times S_{HBr})]-[(n_{H_2}\times S_{H_2})+(n_{Br_2}\times S_{Br_2})$

where,

n = number of moles

Now put all the given values in this expression, we get

$20.1=[(2\times 198.5)]-[(1\times 130.6)+(1\times S_{Br_2})$

$S_{Br_2})=246.3$

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