Calculate equivalent Resistance between points P and Q.
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Answers
Analysis→
Here we're given a circuit diagram in which a 1Ω resistor connected with two 3Ω resistors in parallel which is further connect with three 3Ω resistors in parallel. And we've to find the total effective resistance between the points P and Q. And we know that :
Given→
- Resistor in series=1Ω
- Resistors in parallel=Two 3Ω
- Resistors in parallel=Three 3Ω
To Find→
The total effective resistance between P and Q
Answer→
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Refer to the pic provided for simplification of parallel resistors :)
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Now we've simplified all the resistors in parallel. And are left with only Three resistors in series. So let's solve them and find the equivalent resistance ahead »
☞ Hence the equivalent resistance between P and Q is 3.5Ω which is the required answer.
View the answer in the website to see correct coding as there Ømega will be displayed as Ω.
HOPE IT HELPS.
Given : A circuit
To Find : equivalent Resistance between points P and Q.
Solution:
in parallel 1/R = 1/R₁ + 1/R₂ + .. + 1/Rₙ
in series = R = R₁ + R₂ + .. + Rₙ
3 resistance of 3 Ω are in parallel
1/R = 1/3 + 1/3 + 1/3
=> 1/R = 3/3
=> 1/R = 1
=> R = 1 Ω
2 Resistance of 3 Ω are in parallel
=> 1/R = 1/3 + 1/3
=> 1/R = 2/3
=> R = 3/2
=> R = 1.5 Ω
Now 1 Ω , 1.5 Ω and 1 Ω are in series
Hence R = 1 + 1.5 + 1
= 3.5 Ω
equivalent Resistance between points P and Q = 3.5 Ω
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