Calculate equivalent resistance when two 10ohm resistors are connected in series?
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Answered by
2
Answer:
given,
R1 = R2= 10 Ω
equivalent resistance , R , connected in series = R1 + R2 = 10 + 10 = 20Ω.
so
, equivalent resistance is 20Ω.
Answered by
5
Equivalent resistance = 20 Ω when 2 , 10ohm resistors are connected in series
Explanation:
Two resistance 10 Ω each
Resistance in Series are added
=> equivalent resistance = 10 + 10 = 20 Ω
Let say two Resistance R₁ & R₂ are in series the current will be same flowing through them . let say I
=> V = IR
=> V = IR₁ + IR₂
=> IR = IR₁ + IR₂
=> R = R₁ + R₂
if resistance are in parallel then
1/Req = 1/R₁ + 1/R₂
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