Question

calculate escape velocity of an object of mass 50kg from surface of earth​

Answer 1

Concept : "Escape velocity of the body does not depends upon mass of it."

Escape velocity = (2gr)^1/2

g = gravitation acceleration = 9.8 m/s^2

r = radius of earth = 6400 km

Escape velocity = 11.2 km/s

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Answer 2

Answer:

Given:

50 kg object has been provided.

To find:

Escape Velocity of the object from the Earth surface.

Definition:

Escape velocity is the velocity of projection of an object from the surface of a planet such that the object goes out of the gravitational pull of the planet.

Formulas used:

$v \: esc. = \sqrt{ \frac{2Gm}{r} }$

G => Universal Gravitational constant,

m => mass of Earth

r => Radius of Earth.

Calculation:

From the formula, we can easily understand that the Escape velocity is not dependent on the mass of the object.

$v \: = \sqrt{ \frac{2 \times (6.673 \times {10}^{ - 11}) \times (6 \times {10}^{24} ) }{6.4 \times {10}^{6} } }$

$= > v = 11.2 \: km {sec}^{ - 1}$

So the escape Velocity for that object from earth surface is 11.2 km/sec.