Calculate Fermi function for an energy KT above the Fermi energy
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Answered by
21
Answer:
0.269
Explanation:
Given:
Fermi function f(E)=?
Boltzmann's constant k= 1.38×10^-(23)J/K
Kelvin's temperature T=300 K
Formula,
f(E)= 1/(1+e^((E-Ef)/k)
Here,(E-Ef)=kT Then
f(E)= 1/(1+e)
= 1/(1+2.78)
=1/3.78
=0.269
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