Calculate final molarity of solution 10.4gram sal ammoniac the n 40ml water having density 1.0726
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Explanation:
use the formula
*m= no. of moles of solute(n) / vol of solutn(L)*
here vol of soln is 40ml. convert into Litre by 40/1000.
for n ie no of moles use *n=given mass(m) / molar massl(w)*
m is 10.4, w is 17(NH3=(N=14 +H=3)
OKAY i seriously dont know the role of given density coz acc to density formula(d=mass/vol), mass, vol and density are given so whats the use of density over here?
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