Calculate final molarity of solution formed by mixing 20ml 0.6M sal ammoniac 500ml 0.4M ferric chloride mixed together
Answers
Answer:
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Explanation:
20mL of 0.2M Al
2
(SO
4
)
3
is mixed with 20mL of 6.6M BaCl
2
Concentration of Cl
−
=
Total volume
Total amount of chloride
Total amount of chloride ion in solution =2×20ml×6.6mmol/ml=264mmol
Total volume =20+20=40mL
∴ Concentration of Cl
−
ion =
40
264
=6.6M .
Answer:
You can solve for the concentration or volume of the concentrated or dilute solution using the equation: M1V1 = M2V2, where M1 is the concentration in molarity (moles/Liters) of the concentrated solution, V2 is the volume of the concentrated solution, M2 is the concentration in molarity of the dilute solution
Concentration of Cl
−
=
Total volume
Total amount of chloride
Total amount of chloride ion in solution =2×20ml×6.6mmol/ml=264mmol
Total volume =20+20=40mL
∴ Concentration of Cl
−
ion =
40
264
=6.6M
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