Physics, asked by Shadow872, 1 year ago

Calculate first and last line for balmer series in a constant

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Answered by ujjwalrra853

For 1st line in Balmer series n1 =2,n2=3 1/λ1= 109678[ 1/n12 -1/n22 ] =109678[1/22-1/32] =109678*5/36 cm-1 =15233 cm-1 λ1=6.56*10-5 cm wavelength of last line λ2 1/ λ2=109678[ 1/n12 -1/n22 ] =109678[ 1/22 -1/∞ ] λ2=1/109678 =3.65*10-5cm

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