calculate focal length of corrective lens having power +2.5D
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Answer:
Focal length = 40 cm
Step-by-step explanation:
We know that P = 1/F where focal length is in metre.
So substitute the values in this formula and you get
2.5 = 1/F
F = 1/2.5
F = 0.4 m
Therefore F = 40 cm ( 1 m = 100 cm )
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