calculate force between two protons of charge 1.6×10-¹⁹ c separated by 5 × 10 -¹⁵m.(nucleus)
Answers
Answer:
Explanation:
- - OVER - -
PHYSICS
WORKSHEET
COULOMB'S LAW
KEY
1 2
2 e
q q F k
d =
electrical proportionality constant = 9.0 x 109
Nm2
/C
charge of a proton = +1 = 1.6 x 10-19 C
charge of an electron = -1 = -1.6 x 10-19 C
1. A charge of 5.67 x 10-18 C is placed 3.5 x 10-6
m away from another charge of – 3.79 x 10-19
C. What is the force of attraction between them?
Data Equation Math Answer
q1 = 5.67 x 10-18 C
q2 = – 3.79 x 10-19 C
d = 3.5 x 10-6
m
1 2
2 e
q q F k
d =
5.67 x 10-18 C x –3.79 x 10-19=2.15 x 10-36
(3.5 x 10-6
)
2 = 1.22 x 10-11
2.15 x 10-36 ÷ 1.22 x 10-11 = 1.76 x 10-25
1.76 x 10-25 x 9 x 109 =
1.58 x 10-15 N
2. What is the magnitude of electrical force of attraction between an iron nucleus (26 protons)
and its innermost electron if the distance between them is 1.0 x 10-12 m?
Data Equation Math Answer
q1 = 26+
q2 = 1-
d = 1.0 x 10-12
m
1 2
2 e
q q F k
d =
q1 = 26(1.6 x 10-19) = 4.16 x 10-18
q2 = 1(-1.6 x 10-19) = -1.6 x 10-19
4.16 x 10-18x -1.6 x 10-19= -6.66 x10-37
(1.0 x 10-12)
2 = 1.0 x 10-24
-6.66 x10-3 ÷1.0 x 10-24 = -6.66 x 10-13
-6.66 x 10-13 (9 x 109
)
-5.99 x 10-3 N
3. Two groups of three protons each are located at two of the opposite corners of a square with
10 cm sides. Calculate the force between them.
Data Equation Math Answer
q1 = 3+
q2 = 3+
d = 0.14 m 1 2
2 e
q q F k
d =
q1 = 3(1.6 x 10-19) = 4.8 x 10-19
4.8 x 10-19
x4.8 x 10-19
= 2.3 x 10-37
(0.14)2 = 0.0196
2.3 x 10-37÷(0.0196) = 1.17 x 10-35
1.17 x 10-35(9 x 109
)
1.06 x 10-25 N
4. How far apart must two electrons be if the force between them is 1.0 x 10-12
N?
Data Equation Math Answer
q1 = 1-
q2 = 1-
Fe = 1.0 x 10-12 N
k = 9 x 109
= �12
q1 = q2 = -1.6 x 10-19
9 x 109 x -1.6 x 10-19 x -1.6 x 10-19=
2.3 x 10-28
2.3 x 10-28 ÷ 1.0 x 10-12 = 2.3 x 10-16
16 2.3 10 x −
1.52 x 10-8 m
5. A force of 3.24 x 10-10
N exists between a +18 charge and another mystery particle. The ions
are 2.53 x 10-8
m apart. What is the charge of the mystery particle?
Data Equation Math Answer
Fe = 3.24 x 10-10 N
q1= 18+
d = 2.53 x 10-8 m
k = 9 x 109 1 = 2
1
3.24 x 10-10 (2.53 x 10-8
)
2 =2.07x10-25
18 (1.6 x 10-19) = 2.88 x 10-18
9 x 109 (2.88 x 10-18) = 2.59 x 10-8
2.07x10-25 ÷ 2.59 x 10-8 = 7.99 x 10-18
7.99 x 10-18 ÷ 1.6 x 10-19
50 +