Question

calculate force between two protons of charge 1.6×10-19C separated by 5×10-15m.(nucleus)​

Answer 1

F= (1/4πε0)× q1q2/r²

q1=q2= 1.6×10-¹⁹

r= 5×10-¹⁵

1/4πε0 = 9 × 10^9

F= 9.216 N