calculate force between two protons of charge 1.6×10-19C separated by 5×10-15m.(nucleus)
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F= (1/4πε0)× q1q2/r²
q1=q2= 1.6×10-¹⁹
r= 5×10-¹⁵
1/4πε0 = 9 × 10^9
F= 9.216 N
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