Question

calculate force of repulsion Between two point charge of 10^-8 C and 10^-6 C separated by a distance of 0.05m?​

Answer 1

Answer:

F=q1q2/r^2

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Answer 2

Answer:

3.6 x 10^-2 N

Explanation:

We know, by coulomb's law

F= 1/4πε Q1Q2/r^2                  

value of  1/4πε = 9x10^9

now substitute the values.

F = 9 x 10^9  x  10^-8 x 10^-6  / 0.05^2

Force = 9 x 10^-5 / 0.0025 = 3600 x 10^-5

              3.6 x 10^-2 N

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