Question

calculate free energy changes for expansion of 8 moles of an ideal gas from 1atm to 0.1 atm at 25​

Answer 1

Answer:

Given :- P

1

=1 bar P

2

=0.1 bar T

c

=273K

n=1mole; Isothermal process T=const

ΔU=Q+W ---- in isothermal process ΔU=0

⇒Q=−W

Now,

W=−P

1

V

1

ln

V

1

V

2

or −nRTln

V

1

V

2

⇒W= −nRT

P

2

P

1

W=−1×8.314×273×ln(

0.1

1

)

W=−8.314×273×ln10

W=−5226.23 J

∴Q=5226.23 J