Calculate freezing point depression expected for 0.0711 n aqueous
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Answered by
13
Answer:
Explanation:
Here m=0.0711m
ΔTf=0.320∘C
Kf=1.86∘Cmol−1
ΔTf=iKfm
i=ΔTfKf×m
=0.3201.86×0.0711
=0.3200.132
=2.4
Answered by
52
Explanation:
Depression in freezing point of a solvent upon aaddition of solute is given as: Δ Tf = m.Kf m = molality of the solution = 0.0711 kg/mol Kf = cryoscopic ...
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