Calculate freezing point of a 0.25m solution of urea in water if the molar depression constant is 1.8Kkgmol-1
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Molal depression constant = 1.8 °K / (mol/kg)
Molarity given = 0.25 M = 0.25 moles/liter
1 liter of water weighs 18 gms
So moles/kg of Urea = 0.25 * 1000/18 = 125/9 moles/kg
Depression in freezing point = 1.8 * 125/9 = 25°C
Freezing point of pure water = 0°C
Hence the freezing point is - 25°C
Molarity given = 0.25 M = 0.25 moles/liter
1 liter of water weighs 18 gms
So moles/kg of Urea = 0.25 * 1000/18 = 125/9 moles/kg
Depression in freezing point = 1.8 * 125/9 = 25°C
Freezing point of pure water = 0°C
Hence the freezing point is - 25°C
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