Question

calculate Frequency of a badiation with wave
length 48ohm​

Answer 1

Answer:

Wavelength of light =5800×10

−10

m

frequency =

wavelength

C

=

5800×10

−10

3×10

8

=0.05×10

16

wave no.is reciprocal  of wavelength wave no. = 

wavelength

1

=0.017×10

8

m

−1

Answer 2

Answer:

$\blue{\mathfrak{\underline{\large{Given}}}:} \\ c = 3 \times {10}^{8} \: {ms}^{ - 1} \\ λ = 48 \: m\\ frequency = \frac{speed \: of \: ligt}{wavelength} \\ υ = \frac{c}{λ} \\ υ = \frac{3 \times {10}^{8} }{48} \\ υ = 0.0625 \times {10}^{8} \\ \boxed{υ = 6.25 \times {10}^{6} \: Hz } \\ \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \blue{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}$