Question

Calculate frequency of oscillation of simple pendulum of length 9 cm on Earth.

Answer 1

Given:

Length of Pendulum, l= 9cm= 0.09m

To Find:

Frequency of oscillation of simple pendulum

Solution:

We know that,

• For a simple pendulum

$\bf{Frequency=\dfrac{1}{Time\:Period}}$

$\bf{}$$\bf{Time\:Peroid=2\pi\sqrt{\dfrac{l}{g}}}$

where,

l is the length of the pendulum

g is acceleration due to gravity

So, for given pendulum

$\longrightarrow\mathrm{Time\:Peroid=2\pi\sqrt{\dfrac{l}{g}}}$

$\longrightarrow\mathrm{Time\:Peroid=2\pi\sqrt{\dfrac{0.09}{10}}}$

(Taking value of 'g' as 10 m/s²)

$\longrightarrow\mathrm{Time\:Peroid=2\pi\sqrt{0.009}}$

$\longrightarrow\mathrm{Time\:Peroid=2\pi\sqrt{9(0.001)}}$

$\longrightarrow\mathrm{Time\:Peroid=2\pi(3)\sqrt{0.001}}$

$\longrightarrow\mathrm{Time\:Peroid=6\pi\sqrt{0.001}}$

$\longrightarrow\mathrm{Time\:Peroid=6\pi(0.03)}$

$\longrightarrow\mathrm{Time\:Peroid=0.18\pi}$

$\longrightarrow\mathrm{Time\:Peroid=0.18\times\dfrac{22}{7}}$

$\longrightarrow\mathrm{Time\:Peroid=0.56\:s}$

Now,

$\longrightarrow\mathrm{Frequency=\dfrac{1}{Time\:Period}}$

$\longrightarrow\mathrm{Frequency=\dfrac{1}{0.56}}$

$\longrightarrow\mathrm{Frequency=1.78\:Hz}$

Hence, the frequency of oscillation of given simple pendulum is 1.78 Hz.

Answer 2

Answer: REFER UR T.B SELINA CONCISE

Explanation: