Calculate ∆G° Au +Ca^2(1M) -- Au^+3 (1M)+Ca
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ANSWER
E
cell
o
=E
Ca
2+
/Ca
o
−E
Au
3+
/Au
o
=(−2.87V)−(1.50V)=−4.37V
Δ
r
G
cell
o
=−6×96500×(−4.37V)
=+2530.230kJ/mol
Since Δ
r
G
o
is positive , therefore , reaction is non-spontaneous.
Au
3+
/Au half cell will be an oxidizing agent while Ca
2+
/Ca half cell will be a reducing agent.
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