Chemistry, asked by Anonymous, 1 year ago

Calculate ◇G° for the following reaction:

CO+1/2 O2------> CO2
◇H°=-282.84kJ
Given

S°co2 = 213.8KJ^-1 mol^-1
S°co=197.9JK^-1 mol^-1
S°o2 = 205.0JK^-1 mol^-1


Answers

Answered by Anonymous
4

◇S°r= S°co2-Sco-1/2◇S°o2

=213.8-197.9-1/2×205.0=213.8-197.9-102.5

=231.8-300.4=-86.6

◇G°=◇H°-T◇S°

=-282.84kJ - 298(-86.6)

=-282840 J + 25806 =-257033.2=-257.033 kJ mol^-1

Answered by MarshmellowGirl
10

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