Question

calculate gram atom of sulphur in 4.8 grams of sulphur dioxide?​

Answer 1

Explanation:

By theory we can say 1 gram of SO2=1mole SO2

So

1mole SO2=mass/molar mass

=

$\frac{4.8}{32 + 2 \times 16}$

$\frac{4.8}{32 + 2 \times 16}$

$\frac{4.8}{64}$

by solving you will get the answer

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