Question

calculate gravotational force of attraction between earth and jupiter?​

Answer 1

Answer:

F=Gm1m2r2

where

G is the gravitational constant = 6.67×10−11m3kg−1s−2

m1 is the mass of the Earth = 5.97×1024kg

m2 is the mass of Jupiter = 1.89×1027kg

r is the distance between them, from 5.88×1012 to 9.68×1012 meters

Plugging in the gravitational constant and masses into the formula, the gravitational attraction between the Earth and Jupiter as a function of distance is

F=6.67×10−11m3kg−1s−25.97×1024kg×1.89×1027kgr2

F=6.67×10−11m3kg−1s−21.13×1052kg2r2

F=6.67×10−11m3kg−1s−21.13×1052kg2r2

F=7.53×1041m3kgs−2r2

For r=5.88×1012m (the minimum distance between the Earth and Jupiter):

F=7.53×1041m3kgs−2(5.88×1012m)2

F=7.53×1041m3kgs−23.45×1025m2

F=2.18×1016mkgs−2=2.18×1016Newtons

For r=9.68×1012m (the maximum distance between the Earth and Jupiter):

F=7.53×1041m3kgs−2(9.68×1012m)2

F=7.53×1041m3kgs−29.37×1025m2

F=8.03×1015mkgs−2=8.03×1015Newtons