Question

calculate ∆H for the reaction
CH2Cl2(g)------------->C(g) + 2H(g) + 2Cl(g).

the average bond energy of C-----H Bond and C--------Cl bond are 415.0 kg/ mol and 326.0 kg per mole respectively ​

Answer 1

Answer:

in this reaction

Two C-----H and Two C-----Cl ponds are to be broken so that..

∆H = 2 (bond energy of C------H bond) + 2 (bond energy of C------Cl bond)

= 2(415.0) + 2(326.0)

= 830 + 652

= 1482 kJ

Answer 2

✄┈┈┈┈┈┈┈┈┈┈┈┈┈┈« Two C-----H and Two C-----Cl ponds are to be broken so that..  ∆H = 2 (bond energy of C------H bond) + 2 (bond energy of C------Cl bond)  = 2(415.0) + 2(326.0)   = 830 + 652   = 1482 kJ »—————————–✄